Question

How to find the harmonic value of N (1 + 1/2 + 1/3 + ... 1/N) in TypeScript

Answer 1

// harmonic value of N  = (1 + 1/2 + 1/3 + ... 1/N)

function getHarmonicValue(n: number): number {
    let hv: number = 0.0;

    for (let i: number = 1; i <= n; i++) {
        hv += 1 / i;
    }

    return hv;
}

function getHarmonicValueRecursion(n: number): number {
    if (n === 1) { 
        return 1.0; 
    } else { 
        return 1.0 / n + getHarmonicValueRecursion(n - 1); 
    }
}

const n: number = 7;

console.log("Harmonic value: " + getHarmonicValue(n));
console.log("Harmonic value: " + getHarmonicValueRecursion(n));



/*
run:
   
"Harmonic value: 2.5928571428571425" 
"Harmonic value: 2.5928571428571425" 
   
*/

 

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