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How to call a function after a delay of N seconds in Python



98 views
asked Oct 12, 2024 by avibootz
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1 Answer

0 votes 
import threading
import time

def func():
  print("func()")
  
seconds = 2
t = threading.Timer(seconds, func)
t.start()


'''
run:

func()

'''

 



answered Oct 12, 2024 by avibootz

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