Question

How to check whether a number is a perfect cube root in C#

Answer 1

// The cube root is a whole number. For example, 27 is a perfect cube, as ∛27 or (27)**1/3 = 3

using System;

public class PerfectCubeRoot_CSharp
{
	public static bool isPerfectCubeRoot(int x) {
		x = Math.Abs(x);

		int cubeRoot = (int)Math.Round(Math.Pow(x, 1.0 / 3.0), MidpointRounding.AwayFromZero);

		return Math.Pow(cubeRoot, 3) == x;
	}

	public static void Main(string[] args)
	{
		Console.WriteLine(isPerfectCubeRoot(16));
		Console.WriteLine(isPerfectCubeRoot(64));
		Console.WriteLine(isPerfectCubeRoot(27));
		Console.WriteLine(isPerfectCubeRoot(25));
		Console.WriteLine(isPerfectCubeRoot(-64));
		Console.WriteLine(isPerfectCubeRoot(-27));
		Console.WriteLine(isPerfectCubeRoot(729));
	}
}



/*
run:
  
false
true
true
false
true
true
true
  
*/

 

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