Question

How to compare two strings lexicographically in TypeScript

Answer 1

function compare(a: string, b: string) {
    return a.localeCompare(b);
}
 
console.log(compare("aa", "ab")); // <
console.log(compare("a", "b"));   // <
console.log(compare("a", "c"));   // <
 
console.log("aaa".localeCompare("abc"));   // <
console.log("aaab".localeCompare("aapa")); // <
 
console.log(compare("aa", "aa")); // ==
 
console.log(compare("ba", "aa")); // >
console.log(compare("ca", "aa")); // >
console.log(compare("ab", "aa")); // >
console.log(compare("b", "a"));   // > 
console.log(compare("b", "aac")); // > 


    
/*
run:
    
-1
-1
-1
-1
-1
0
1
1
1
1
1
    
*/

 

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