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How to find the ceiling value of a number using ceil() function in Rust

1 Answer

0 votes
// ceil(self) -> f64 - Returns the smallest integer greater than or equal to self

use std::f64;

fn main() {
    println!("{}", f64::ceil(13.0));
    
    println!("{}", f64::ceil(13.1));
    
    println!("{}", f64::ceil(15.4));
    println!("{}", f64::ceil(15.5));
    println!("{}", f64::ceil(15.6));
    
    println!("{}", f64::ceil(4.4));
    println!("{}", f64::ceil(4.5));
    println!("{}", f64::ceil(4.6));
    
    println!("{}", f64::ceil(-50.0));
    
    println!("{}", f64::ceil(-7.4));
    println!("{}", f64::ceil(-7.5));
    println!("{}", f64::ceil(-7.6));
    
    println!("{}", f64::ceil(0.0));
}


    
    
/*
run:
 
13
14
16
16
16
5
5
5
-50
-7
-7
-7
0
 
*/

 



answered Aug 11, 2024 by avibootz

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