Question

How to check if an array contains a pair of numbers whose product is odd in JavaScript

Answer 1

// A produce of a pair of integers will always be odd if at least 2 of them are odd

function arrayContainsAPairOfOddProduct(arr) {
    let oddCount = 0;

    for (let i = 0; i < arr.length; i++) {
        if (arr[i] % 2 !== 0) {
            oddCount++;
            if (oddCount === 2) {
                break;
            }
        }
    }

    return oddCount > 1;
}

const arr = [2, 2, 4, 4, 6, 6, 7, 10, 10, 9]; // 7 * 9 = 63 -> Odd

console.log(arrayContainsAPairOfOddProduct(arr));



/*
run:

true

*/

 

70+ SQL courses for beginners and professionals