Question

How to pass struct to function by address in C

Answer 1

#include <stdio.h>
#include <string.h>

typedef struct user {
    char name[32];
    int age;
} user;
 
void print(user u) {
    printf("%s %d\n", u.name, u.age);
}
 
void set(user *u) {
    u->age = 102;
}
 
int main()
{
    user u = { "Jar Jar Binks", 56 };
     
    print(u);
 
    set(&u); // by address
 
    print(u);
}


 
/*
run:
 
Jar Jar Binks 56
Jar Jar Binks 102
 
*/ 
   
   
   
/*
run:
   
abde
abcef
   
*/

 

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