Question

How to initialize char array with random characters in C

Answer 1

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

#define SIZE 10

void initialize_char_array_with_random_characters(char arr[], int size) {
    const char characters[] = "0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ";
    int characters_count = sizeof characters;
    
    srand(time(NULL));
       
    for (size_t i = 0; i < size; i++) {
        arr[i] = characters[rand() % characters_count];
    }
}

int main() {
    char arr[SIZE + 1] = "";

    initialize_char_array_with_random_characters(arr, SIZE);

    for (int i = 0; i < SIZE; i++) {
        printf("%c ", arr[i]);
    }

    return 0;
}

 
 
 
/*
run:
 
a J y F 8 1 l E 4 I 
 
*/

 

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