Welcome to collectivesolver - Programming & Software Q&A with code examples. A website with trusted programming answers. All programs are tested and work.

Contact: aviboots(AT)netvision.net.il

Buy a domain name - Register cheap domain names from $0.99 - Namecheap

Scalable Hosting That Grows With You

Secure & Reliable Web Hosting, Free Domain, Free SSL, 1-Click WordPress Install, Expert 24/7 Support

Semrush - keyword research tool

Boost your online presence with premium web hosting and servers

Disclosure: My content contains affiliate links.

39,938 questions

51,875 answers

573 users

How to find all the possible rows which are permutations of a given row in a matrix with Java

1 Answer

0 votes
import java.util.LinkedHashSet;

public class Program
{
    public static void printPermutationRows(int matrix[][], int givenrow) {
        int rows = matrix.length;
        int cols = matrix[0].length;
        
        LinkedHashSet<Integer> Set = new LinkedHashSet<>();
        for (int j = 0; j < cols; j++) {
            Set.add(matrix[givenrow][j]);
        }
        
        for (int i = 0; i < rows; i++) {
            if (i == givenrow) {
                continue;
            }
            int j;
            for (j = 0; j < cols; j++) {
                if (!Set.contains(matrix[i][j])) {
                    break;
                }
            }
            if (j != cols) {
                continue;
            }
            
            System.out.print(i + ", ");
        }
    }
    public static void main(String[] args)
    {
        int  givenrow = 1;

        int matrix[][] = {
            {7, 9, 4, 3, 1},
            {4, 7, 9, 1, 3},
            {4, 7, 8, 1, 2},
            {1, 6, 9, 7, 4},
            {9, 1, 3, 7, 4},
        };

        printPermutationRows(matrix, givenrow);
    }
}  
     
     
     
/*
run:

0, 4,  
  
*/

 



answered Feb 20, 2024 by avibootz
edited Feb 20, 2024 by avibootz
...