Question

How to convert integer to char array in C

Answer 1

#include <stdio.h>

int main() {
    int num = 890347;
    char buf[32] = "";
 
    sprintf(buf, "%d", num);
     
    puts(buf);
     
    for (int i = 0; buf[i] != '\0'; i++) {
        printf("%c, ", buf[i]);
    }
 
    return 0;
}
 
 
 
/*
run:
 
890347
8, 9, 0, 3, 4, 7, 
 
*/

 

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