Question

How to check whether the type of a variable is integer in PHP

Answer 1

$arr = array(100, 3.14, "76", "102.6", 1000000000, null, true, false);
foreach ($arr as $value) 
{
    if (is_int($value))
        echo $value . " - int <br />\n";
    else
        echo $value . " - not int <br />\n";
}


/*
run: 

100 - int 
3.14 - not int 
76 - not int 
102.6 - not int 
1000000000 - int 
- not int 
1 - not int 
- not int  

*/

 

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