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How to calculate the series 1 2 3 6 9 18 27 54 81 162 243 ... N in Python

1 Answer

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# 1 2 3 6 9 18 27 54 81 162 243 ... N 
    
# (1) (2) 1 * 3 (3) 2 * 3 (6) : 3 * 3 (9) 6 * 3 (18) :
# 9 * 3 (27) 18 * 3 (54) : 27 * 3 (81) 54 * 3 (162) :
# 81 * 3 (243)

a = 1
b = 2
total = 11

print(a, b, end=" ")

i = 3
while (i <= total) :
    if (i % 2 == 1) :
        a = a * 3
        print(a, end=" ")
    else :
        b = b * 3
        print(b, end=" ")
    i += 1
   
    
   
    
'''
run:

1 2 3 6 9 18 27 54 81 162 243 

'''

 



answered Jan 17, 2024 by avibootz

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