Question

How to extract the last N bits of a 32-bit integer in Java

Answer 1

public class MyClass {
    private static int get_last_N_bits(int number, int N) {
	    int mask = (1 << N) - 1;
        
        return number & mask;
    }
    
    public static void main(String args[]) {
        int number = 441; // 00000001101-11001
	    int N = 5;

	    System.out.println(String.format("%16s", Integer.toBinaryString(number)).replaceAll(" ", "0"));

        int lastNbits = get_last_N_bits(number, N);

        System.out.println(String.format("%16s", Integer.toBinaryString(lastNbits)).replaceAll(" ", "0"));  
    }
}





/*
run:
    
0000000110111001
0000000000011001
    
*/

 

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