Question

How to reverse the bits of a number in Python

Answer 1

def reverse_bits(num):
    total_bits = 32
    reverse_bits = 0
    
    for i in range(total_bits):
        if (num & (1 << i)):
            reverse_bits |= 1 << ((total_bits - 1) - i)
    
    return reverse_bits
 
num = 42
print('{:032b}'.format(num))
num = reverse_bits(num)
print('{:032b}'.format(num) + '\n')

num = 19
print('{:032b}'.format(num))
num = reverse_bits(num)
print('{:032b}'.format(num))




'''
run:

00000000000000000000000000101010
01010100000000000000000000000000

00000000000000000000000000010011
11001000000000000000000000000000
 
'''

 

70+ SQL courses for beginners and professionals