Question

How to check if an array contains all values from another array in PHP

Answer 1

$array1 = ["a", "b", "c", "d", "e"];
$array2 = ["a", "b", "e"];

if (empty(array_diff($array2, $array1))) {
    echo "array1 contains all values from array2";
} else {
    echo "array1 does not contain all values from array1";
}

 
 
  
  
/*
run:
  
array1 contains all values from array2
 
*/

 

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Answer 2

$array1 = ["a", "b", "c", "d", "e"];
$array2 = ["a", "b", "e"];

if (count(array_intersect($array2, $array1)) == count($array2)) {
    echo "array1 contains all values from array2";
} else {
    echo "array1 does not contain all values from array1";
}

 
  
  
  
/*
run:
  
array1 contains all values from array2
 
*/

 

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