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How to convert digits of 2 power 100 to an array of characters in C

1 Answer

0 votes
#include <stdio.h>
#include <math.h>

int main(void)
{
    int base = 2;
    int exponent = 100;
   
    double power = pow(base, exponent); 
     
    printf("%lf\n", power);

    char array[64] = "";

    snprintf(array, 32, "%.32f", power);
    
    for(int i = 0; array[i]; i++) {
        if (array[i] != '.') {
            printf("array[%d] = %c\n", i, array[i]);
        }
    }  
     
    return 0;
}
  
   
   
   
/*
run:

1267650600228229401496703205376.000000
array[0] = 1
array[1] = 2
array[2] = 6
array[3] = 7
array[4] = 6
array[5] = 5
array[6] = 0
array[7] = 6
array[8] = 0
array[9] = 0
array[10] = 2
array[11] = 2
array[12] = 8
array[13] = 2
array[14] = 2
array[15] = 9
array[16] = 4
array[17] = 0
array[18] = 1
array[19] = 4
array[20] = 9
array[21] = 6
array[22] = 7
array[23] = 0
array[24] = 3
array[25] = 2
array[26] = 0
array[27] = 5
array[28] = 3
array[29] = 7
array[30] = 6

*/

 



answered Nov 10, 2023 by avibootz

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