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How to extract odd numbers from an int array in Java

1 Answer

0 votes
import java.util.Arrays;

public class MyClass {
    public static int getTotalOddNumbers(int array[]) {
        int totalOdd = 0;
        for (int i : array) {
             if (i % 2 != 0) {
                totalOdd++;
            }
        }
        return totalOdd;
    }
    
    public static void setOddNumbers(int array[], int oddNumbers[]) {
        int i = 0;
        for (int num : array) {
            if (num % 2 != 0) { 
                oddNumbers[i++] = num;
            }
        }
    }

    public static void main(String args[]) {   

        int array[] = {2, 5, 1, 9, 8, 0, 4, 7, 3};
      
        int oddNumbers[] = new int[getTotalOddNumbers(array)];
        
        setOddNumbers(array, oddNumbers);
      
        System.out.println(Arrays.toString(oddNumbers));
    }
}


   
   
   
/*
run:
   
[5, 1, 9, 7, 3]

*/

 



answered Nov 9, 2023 by avibootz
edited Nov 9, 2023 by avibootz
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