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How to generate an array of strings numbers with a specific range in PHP

3 Answers

0 votes
// range(string|int|float $start, string|int|float $end, int|float $step = 1): array

$array_strings = array_map('strval', range('0000000000', '9999999999', '1111111111'));
var_dump($array_strings);


 
 
/*
run:
 
array(10) {
  [0]=>
  string(1) "0"
  [1]=>
  string(10) "1111111111"
  [2]=>
  string(10) "2222222222"
  [3]=>
  string(10) "3333333333"
  [4]=>
  string(10) "4444444444"
  [5]=>
  string(10) "5555555555"
  [6]=>
  string(10) "6666666666"
  [7]=>
  string(10) "7777777777"
  [8]=>
  string(10) "8888888888"
  [9]=>
  string(10) "9999999999"
}

*/

 



answered Sep 22, 2023 by avibootz
0 votes
// range(string|int|float $start, string|int|float $end, int|float $step = 1): array

$range = range('0000000000', '9999999999', '1111111111');

$array_strings = array_map(function($range) {
    return str_pad($range, 10, '0', STR_PAD_LEFT); 
}, $range);

var_dump($array_strings);


 
 
/*
run:
 
array(10) {
  [0]=>
  string(10) "0000000000"
  [1]=>
  string(10) "1111111111"
  [2]=>
  string(10) "2222222222"
  [3]=>
  string(10) "3333333333"
  [4]=>
  string(10) "4444444444"
  [5]=>
  string(10) "5555555555"
  [6]=>
  string(10) "6666666666"
  [7]=>
  string(10) "7777777777"
  [8]=>
  string(10) "8888888888"
  [9]=>
  string(10) "9999999999"
}

*/

 



answered Sep 22, 2023 by avibootz
0 votes
// range(string|int|float $start, string|int|float $end, int|float $step = 1): array

$range = range('0000000000', '9999999999', '1111111111');

$array_strings = array_map(function($range) {
    return sprintf('%010d', $range); 
}, $range);

var_dump($array_strings);


 
 
/*
run:
 
array(10) {
  [0]=>
  string(10) "0000000000"
  [1]=>
  string(10) "1111111111"
  [2]=>
  string(10) "2222222222"
  [3]=>
  string(10) "3333333333"
  [4]=>
  string(10) "4444444444"
  [5]=>
  string(10) "5555555555"
  [6]=>
  string(10) "6666666666"
  [7]=>
  string(10) "7777777777"
  [8]=>
  string(10) "8888888888"
  [9]=>
  string(10) "9999999999"
}

*/

 



answered Sep 22, 2023 by avibootz
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