Question

How to calculate the total of all possible binary options of N bits in C

Answer 1

#include <stdio.h>
#include <math.h>

int main() {
    int N = 4;
    printf("%d\n", 1 << N); // = 2 ^ N
         
    N = 5;
    printf("%d\n", 1 << N); // = 2 ^ N
         
    N = 6;
    printf("%.2f\n", pow(2, N));
    printf("%d\n", (int)pow(2, N));
    
    return 0;
}




/*
run:

16
32
64.00
64

*/

 

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