How to generate all the binary options of N bits in TypeScript

1 Answer

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function generateAllBinaryOptions(N: number) {
    let binary: any[] = [];

    const total_bits = parseInt("1".repeat(N), 2) + 1;

    for (let i: number = 0; i < total_bits; i++) {
        binary.push(i.toString(2).padStart(N, '0'));
    }

  return binary;
}


const N: number = 4;
console.log(generateAllBinaryOptions(N));





/*
run:

["0000", "0001", "0010", "0011", "0100", "0101", "0110", "0111", "1000", "1001", "1010", "1011", "1100", "1101", "1110", "1111"] 

*/

 



answered Aug 26, 2023 by avibootz

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