Question

How to generate all the binary options of N bits in Java

Answer 1

public class MyClass
{
	private static void generateAllBinaryOptions(int N) {
		int total_bits = 1 << N; // = 2 ^ N

		for (int i = 0; i < total_bits; i++) {
			String binary = String.format("%4s", Integer.toBinaryString(i)).replaceAll(" ", "0");

			System.out.println(binary);
		}
	}
	public static void main(String[] args)
	{
		int N = 4;

		generateAllBinaryOptions(N);
	}
}





/*
run:
  
0000
0001
0010
0011
0100
0101
0110
0111
1000
1001
1010
1011
1100
1101
1110
1111
  
*/

 

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