Question

How to count the numbers with even number of digits in an array with C#

Answer 1

using System;

public class Program
{
	private static int count_even_numbers(int[] arr) {
		int result = 0;
		int size = arr.Length;

		for (int i = 0; i < size; i++) {
			int total_digits = (int)(Math.Log10(arr[i])) + 1;

			if (total_digits % 2 == 0) {
				result++;
			}
		}

		return result;
	}
	public static void Main(string[] args)
	{
		int[] array = new int[] {564, 90, 7, 1248, 47325, 834921, 1234567};

		Console.Write(count_even_numbers(array));
	}
}





/*
run:
  
3
 
*/

 

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