Question

How to check if a matrix is symmetric (square matrix that is equal to its transpose) in Python

Answer 1

def checkSymmetric(matrix) :
    rows = len(matrix)
    cols = len(matrix[0])
    
    if (rows != cols) :
        return False
    
    i = 0
    while (i < rows) :
        j = 0
        while (j < cols) :
            if (matrix[i][j] != matrix[j][i]) :
                return False
            j += 1
        i += 1
    return True
        
matrix = [[1, 5, 2, 4], 
          [5, 6, 3, 7], 
          [2, 3, 9, 0], 
          [4, 7, 0, 8]]

if (checkSymmetric(matrix)) :
    print("yes", end ="")
else :
    print("no", end ="")


'''
run:

yes

'''

 

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Answer 2

def checkSymmetric(matrix) :
    rows = len(matrix)
    cols = len(matrix[0])
    
    if (rows != cols) :
        return False
    
    for i in range(rows) :
        for j in range(cols) :
            if (matrix[i][j] != matrix[j][i]):
                return False
    return True
        
matrix = [[1, 5, 2, 4], 
          [5, 6, 3, 7], 
          [2, 3, 9, 0], 
          [4, 7, 0, 8]]

if (checkSymmetric(matrix)) :
    print("yes", end ="")
else :
    print("no", end ="")


'''
run:

yes

'''

 

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Answer 3

def checkSymmetric(matrix):
    rows = len(matrix)
    cols = len(matrix[0])
    
    if (rows != cols):
        return False
    
    transpose = [[(matrix[j][i]) for j in range(rows)] for i in range(cols)]
    
    if (matrix == transpose):
        return True
        
    return False
        
matrix = [[1, 5, 2, 4], 
          [5, 6, 3, 7], 
          [2, 3, 9, 0], 
          [4, 7, 0, 8]]

if (checkSymmetric(matrix)):
    print("yes", end ="")
else :
    print("no", end ="")


'''
run:

yes

'''

 

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