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How to count the frequency of the digits (0 to 9) in a string with VB.NET

1 Answer

0 votes
Imports System

Public Class Program
    Public Shared Sub countDigits(ByVal s As String)
        Dim size As Integer = s.Length

        If size = 0 Then
            Console.Write("String is empry")
            Return
        End If

        Dim digit_frequency As Integer() = New Integer() {0, 0, 0, 0, 0, 0, 0, 0, 0, 0}

        For i As Integer = 0 To size - 1
            If Char.IsDigit(s(i)) Then
                digit_frequency(Convert.ToByte(s(i)) - Convert.ToByte("0"c)) += 1
            End If
        Next

        For j As Integer = 0 To 10 - 1
            Console.WriteLine(j & ": " & digit_frequency(j) & " times")
        Next
    End Sub

    Public Shared Sub Main(ByVal args As String())
		Dim s As String = "vb.net23c++4523java23988rust82215"

        countDigits(s)
    End Sub
End Class




' run:
'
' 0: 0 times
' 1: 1 times
' 2: 5 times
' 3: 3 times
' 4: 1 times
' 5: 2 times
' 6: 0 times
' 7: 0 times
' 8: 3 times
' 9: 1 times
' 

 



answered Jun 1, 2023 by avibootz
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