Question

How to initialize array in struct with zeros and multiple numbers at specific indexes with C

Answer 1

#include <stdio.h>
 
typedef struct {
    int arr[10];
    char ch;
} ST;
 
int main(void) {
 
    static const ST s = { { 7, [4] = 12, 13 }, 'z'};
 
    for (int i = 0; i < 10; i++)
        printf("arr[%d] = %2d\n", i, s.arr[i]);
 
    printf("s.ch = %c\n", s.ch);
 
    return 0;
}
 
 
 
 
 
/*
run:
 
arr[0] =  7
arr[1] =  0
arr[2] =  0
arr[3] =  0
arr[4] = 12
arr[5] = 13
arr[6] =  0
arr[7] =  0
arr[8] =  0
arr[9] =  0
s.ch = z
 
*/

 

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