Question

How to find the element that appears once in array where other elements appear in pairs with Rust

Answer 1

#![allow(non_snake_case)]

fn findElementThatAppearsOnce(arr : [usize; 9]) -> usize {
    let size : usize = arr.len();
    let mut element : usize = arr[0];
    {
        let mut i : usize = 1;
        while i < size {
            element = element ^ arr[i as usize];
            i += 1;
        }
    }
    return element;
}

fn main() {
    let arr: [usize; 9] = [7, 2, 2, 4, 5, 3, 4, 5, 7];

    println!("{}", findElementThatAppearsOnce(arr));
}





/*
run:

3

*/

 

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