How to find all elements (leaders) in an array that are greater than all elements to their right in Rust

1 Answer

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#![allow(non_snake_case)]

fn PrintArrayLeaders(arr : [usize; 10]) {
    let size : usize = arr.len();
    {
        let mut i : usize = 0;
        while i < size {
            let mut j : usize;
            {
                j = i + 1;
                while j < size {
                    if arr[i as usize] <= arr[j as usize] {
                        break;
                    }
                    j += 1;
                }
            }
            if j == size {
                println!("{}", arr[i]);
            }
            i += 1;
        }
    }
}
    
fn main() {
    let arr: [usize; 10] = [1, 99, 16, 5, 75, 9, 50, 60, 0, 19];
    
    PrintArrayLeaders(arr);
}




/*
run:

99
75
60
19

*/


 



answered Apr 13, 2023 by avibootz
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