Question

How to swap two numbers with pointers in C

Answer 1

#include <stdio.h> 

void swap(int *n1, int *n2);

int main(void)
{
    int a = 29, b = 85;
    
    swap(&a, &b);
    
    printf("a = %i b = %i", a, b); // a = 85 b = 29
    
    return 0;
}
void swap(int *n1, int *n2)
{
    int tmp = *n1;
    
    *n1 = *n2;
    *n2 = tmp;
}

/* 
run:

a = 85 b = 29

*/

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