How to check if a value is not a number (NaN) in Python

3 Answers

0 votes
import math
 
val = float('nan')
print(math.isnan(val))

val = 3.14
print(math.isnan(val))

val = (100.0 ** 150) * (100.0 ** 150) 
print(math.isnan(val / val))

 



'''
run:

True
False
True

'''

 



answered Mar 9, 2023 by avibootz
0 votes
import numpy as np
 
val = float('nan')
print(np.isnan(val))

val = 3.14
print(np.isnan(val))

val = (100.0 ** 150) * (100.0 ** 150) 
print(np.isnan(val / val))

 



'''
run:

True
False
True

'''

 



answered Mar 9, 2023 by avibootz
0 votes
import pandas as pd
 
val = float('nan')
print(pd.isna(val))

val = 3.14
print(pd.isna(val))

val = (100.0 ** 150) * (100.0 ** 150) 
print(pd.isna(val / val))

 



'''
run:

True
False
True

'''

 



answered Mar 9, 2023 by avibootz
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