How to use array of pointers to dynamic allocate strings in C

1 Answer

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#include <stdio.h>
#include <string.h>
#include <stdlib.h>

#define ARRAYSIZE 3 
#define BUFFERSIZE 32 

int main(void)
{
    char buffer[BUFFERSIZE] = "";
    char* p[ARRAYSIZE] = { NULL }; 

    for (size_t i = 0; i < ARRAYSIZE; i++) {
        printf("Enter string %zu: ", i);
        scanf("%s", buffer);    
        p[i] = malloc((strlen(buffer) + 1) * sizeof(char)); 
        if (!p[i]) {
            puts("malloc error");
            return 1;
        }
        strcpy(p[i], buffer);              
    }

    for (size_t i = 0; i < ARRAYSIZE; i++) {
        puts(p[i]);
        free(p[i]);
    }

    return 0;
}


/*
run:

Enter string 0: c
Enter string 1: c++
Enter string 2: java
c
c++
java

*/

 



answered Feb 21, 2023 by avibootz

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