Question

How to find the element with minimum occurrences in a list with Python

Answer 1

lst = [1, 3, 1, 1, 4, 4, 5, 5, 4, 2, 2, 2, 3, 3, 3]

print(min(lst, key = lst.count))
 
    
    
    
'''
run:
    
5
  
'''

 

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Answer 2

from collections import Counter

lst = [1, 3, 1, 1, 4, 4, 5, 5, 4, 2, 2, 2, 3, 3, 3]

print(Counter(lst).most_common()[-1][0])
 
    
    
    
'''
run:
    
5
  
'''

 

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Answer 3

import numpy as np

lst = [1, 3, 1, 1, 4, 4, 5, 5, 4, 2, 2, 2, 3, 3, 3]

# (array([1, 2, 3, 4, 5]), array([3, 3, 4, 3, 2]))

print(np.unique(lst, return_counts=True)[0][-1])
 
    
    
    
'''
run:
    
5
  
'''

 

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