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How to initialize array with a default number value in Rust

1 Answer

0 votes
fn main() {
    let arr:[i32; 6] = [-1; 6];
    
    println!("{:?}", arr);
}






/*
run:

[-1, -1, -1, -1, -1, -1]

*/

 



answered Oct 25, 2022 by avibootz

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