Question

How to count consecutive sets of numbers in a list with Python

Answer 1

def countlist(lst):
    result = []
   
    count = 1
    for i in range(len(lst) - 1):
        if lst[i] + 1 == lst[i+1]:
            count += 1
        else:
            result.append(count)
            count = 1

    result.append(count) # for lat count
    
    return result


lst = [1, 6, 7, 8, 9, 10, 2, 8, 13, 14, 15, 18, 30, 31, 32, 33]

print(countlist(lst))



'''
run:

[1, 5, 1, 1, 3, 1, 4]

'''

 

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