Question

How to find all pairs in array that equal to a given sum in TypeScript

Answer 1

function findAllPairs(arr : number[], sum : number) {
    let found : boolean = false;

    for (let i : number = 0; i < arr.length - 1; i++) {
        for (let j : number = i + 1; j < arr.length; j++) {
            if (arr[i] + arr[j] == sum) {
                console.log("arr[" + i + "](" + arr[i] + ") + " + "arr[" + j + "](" + arr[j] + ")");
                found = true;
            }
        }
    }
    if (!found) {
        console.log("Pair not found");
    }
}
        
const arr : number[] = [2, 4, 1, 5, 6, 8, 1];
const sum : number = 10;

findAllPairs(arr, sum);





/*
run:

"arr[0](2) + arr[5](8)"
"arr[1](4) + arr[4](6)"

*/

 

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