Question

How to find two numbers from an array that are just smaller and just greater than N in TypeScript

Answer 1

const arr : number[] = [3, 8, 1, 0, 9, 4, 10, 7, 13, 2, 6];
const size : number = arr.length;
const N = 4;
         
let just_greater = Number.MAX_VALUE;
let just_smaller = Number.MIN_VALUE;
 
for (let i : number = 0; i < size; i++) {
    if (arr[i] > N && arr[i] < just_greater) {
        just_greater = arr[i];
    }
    if (arr[i] < N && just_smaller < arr[i]) {
        just_smaller = arr[i];
    }
}
 
console.log("just_smaller: " + just_smaller);
console.log("N: " + N);
console.log("just_greater: " + just_greater);
 
 
 
 
 
/*
run:
 
"just_smaller: 3" 
"N: 4" 
"just_greater: 6" 
      
*/

 

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