How to count and print triplets from an array with sum smaller than a given value in TypeScript

1 Answer

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const array : number[] = [4, 5, 2, 8, 1, 3, 8, 7, 10];
        
const size : number = array.length;
let sum : number = 11;
let count : number = 0;
        
for (let i : number = 0; i < size - 2; i++) {
    for (let j : number = i + 1; j < size - 1; j++) {
        for (let k : number = j + 1; k < size; k++) {
            if (array[i] + array[j] + array[k] < sum) {
                count++;
                console.log(count + ": " + array[i] + "," + array[j] + "," + array[k]);
            }
        }
    }
}

console.log("Number of Triplets = " + count);





/*
run:

"1: 4,5,1" 
"2: 4,2,1" 
"3: 4,2,3" 
"4: 4,1,3" 
"5: 5,2,1" 
"6: 5,2,3" 
"7: 5,1,3" 
"8: 2,1,3" 
"9: 2,1,7" 
"Number of Triplets = 9" 

*/

 



answered Sep 17, 2022 by avibootz
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