Question

How to sort an array of numeric strings in descending order with TypeScript

Answer 1

function CompareFunction(string1 : string, string2 : string) {
    if (string1.length == string2.length) {
        return parseInt(string2) - parseInt(string1);
    }
    else {
            return string2.length - string1.length;
        }
}
  
 
const arr : string[] = ["7", "0", "55", "8", "9", "6", "3"];
  
arr.sort(CompareFunction);
  
for (let i = 0; i < arr.length; i++) {
    console.log(arr[i]);
}
  
  
  
  
/*
run:
  
"55" 
"9" 
"8" 
"7" 
"6" 
"3" 
"0" 
 
*/

 

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