Question

How to sort an array of numeric strings in ascending order with C

Answer 1

#include <stdio.h>
#include <stdlib.h>

int compare(const void* a, const void* b) {
    return (*(int*)a - *(int*)b);
}

int main()
{
    const char* arr_string[] = { "7", "0", "55", "8", "9", "6" };
    int arr_int[] = { 0, 0, 0, 0, 0, 0 };

    int size = sizeof(arr_string) / sizeof(arr_string[0]);

    for (int i = 0; i < size; i++) {
        arr_int[i] = atoi(arr_string[i]);
    }

    qsort(arr_int, size, sizeof(int), compare);

    for (int i = 0; i < size; i++) {
        printf("%d ", arr_int[i]);
    }

    return 0;
}




/*
run:

0 6 7 8 9 55

*/

 

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Answer 2

#include <stdio.h>
#include <stdlib.h>

int compare(const void* a, const void* b) {
    return (*(long*)a - *(long*)b);
}

int main()
{
    const char* arr_string[] = { "7", "0", "55", "8", "9", "6" };
    long arr_long[] = { 0, 0, 0, 0, 0, 0 };

    int size = sizeof(arr_string) / sizeof(arr_string[0]);

    for (int i = 0; i < size; i++) {
        arr_long[i] = (int)strtol(arr_string[i], (char**)NULL, 10);
    }

    qsort(arr_long, size, sizeof(long), compare);

    for (int i = 0; i < size; i++) {
        printf("%ld ", arr_long[i]);
    }

    return 0;
}




/*
run:

0 6 7 8 9 55

*/

 

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