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How to find the second most frequent character in a string with TypeScript

1 Answer

0 votes
function GetSecondMostFrequentChar(s : string) {
    let count = Array(256).fill(0);  // 256 = ASCII table size
         
    for (let i = 0; i < s.length; i++) {
        count[s.charAt(i).charCodeAt(0)]++;
    }
         
    let first = 0;
    let second = 0;
         
    for (let i = 0; i < 256; i++) {
        if (count[i] > count[first]) {
            second = first;
            first = i;
        }
        else if (count[i] > count[second] && count[i] != count[first]) {
                second = i;
            }
        }
     
    return String.fromCharCode(second);
}
 
const str : string = "bbaddddccceeeee";
         
console.log(GetSecondMostFrequentChar(str));
 
 
 
 
 
/*
run:
 
"d"
 
*/
  
  

 



answered Aug 31, 2022 by avibootz

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