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How to use Array.FindAll<T> method to get all array elements that match a condition in C#

1 Answer

0 votes
using System;
using System.Collections.Generic;

namespace ConsoleApplication_C_Sharp
{
    class Program
    {
        static void Main(string[] args)
        {
            int[] arr = CreateArray(20, 0, 100);
            int lBound = 20;
            int uBound = 70;
            int[] foundItems = Array.FindAll(arr, x => x >= lBound && x <= uBound);

            for (int i = 0; i < foundItems.Length; i++)
                Console.Write("{0}  ", foundItems[i]);
        }

        private static int[] CreateArray(int total_elements, int lower, int upper)
        {
            Random rnd = new Random();
            List<int> list = new List<int>();

            for (int i = 1; i <= total_elements; i++)
                list.Add(rnd.Next(lower, upper + 1));

            return list.ToArray();
        }
    }
}


/*
run:
 
68  46  24  46  22  67  55  64 

*/

 



answered Apr 16, 2016 by avibootz
...