Question

How to find the indexes of all occurrences of an element in array with TypeScript

Answer 1

const arr: Array<number> =  [2, 3, 3, 8, 7, 1, 3, 9, 12, 7, 3, 20, 18, 3];
  
const indexes = [];

for (let index = 0; index < arr.length; index++) {
  	if (arr[index] === 3) {
    	indexes.push(index);
  	}
}

console.log(indexes); 
  
    
    
    
/*
run:
    
[1, 2, 6, 10, 13] 
    
*/

 

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