Question

How to reverse subarray of an array in TypeScript

Answer 1

function reverseSubarray(arr : any, start : number, end : number) {
    if (end > arr.length) {
        console.log("End index out of range");
        return;
    }
       
    const mid_sub = (end - start + 1) / 2;  
       
    for (let i = 0; i < mid_sub; i++) {
         let tmp = arr[start + i];
         arr[start + i] = arr[end - i];
         arr[end - i] = tmp;      
    }
}
 
 
const arr = [ 3, 5, 8, 0, 7, 1, 9, 4, 6 ];
          
const start = 2, end = 6;
          
reverseSubarray(arr, start, end);
   
console.log(arr);
 
 
   
   
   
   
/*
run:
   
[3, 5, 9, 1, 7, 0, 8, 4, 6]
   
*/

 

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