Question

How to check if array contains only numbers in Node.js

Answer 1

function arrayContainsOnlyNumbers(array) {
  	return array.every(element => {
    		return typeof element === 'number';
  	});
}

const arr1 = [1, 2, 3, 4];
const arr2 = [1, 2, 3, 'node.js'];
const arr3 = [1, 2, 3, '4'];
const arr4 = [1, 2, 3, true];

console.log(arrayContainsOnlyNumbers(arr1)); 
console.log(arrayContainsOnlyNumbers(arr2)); 
console.log(arrayContainsOnlyNumbers(arr3)); 
console.log(arrayContainsOnlyNumbers(arr4)); 

  
  
  
  
/*
run:
  
true
false
false
false
  
*/

 

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