Question

How to return an array with odd numbers from existing array in TypeScript

Answer 1

const arr = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12];

const odds = arr.filter(n => n % 2)

console.log(odds); 

  
  
  
  
/*
run:
  
[1, 3, 5, 7, 9, 11] 
  
*/

 

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