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How to use sin() function to get the sine of an angle of N radians in C++

1 Answer

0 votes
#include <iostream>
#include <cmath>

using namespace std;

#define PI 3.14159265

int main()
{
	cout << "sin(PI / 6) = " << sin(PI / 6) << endl;
	cout << "sin(PI / 2) = " << sin(PI / 2) << endl;
	cout << "sin(PI / 180) = " << sin(PI / 180) << endl;
	cout << "sin(-2 * PI / 4) = " << sin(-2 * PI / 4) << endl;
	cout << "sin(+0) = " << sin(0.0) << endl;
	cout << "sin(-0) = " << sin(-0.0) << endl;
	cout << "sin(+1) = " << sin(1.0) << endl;
	cout << "sin(-1) = " << sin(-1.0) << endl;

	return 0;
}

/*
run:

sin(PI / 6) = 0.5
sin(PI / 2) = 1
sin(PI / 180) = 0.0174524
sin(-2 * PI / 4) = -1
sin(+0) = 0
sin(-0) = -0
sin(+1) = 0.841471
sin(-1) = -0.841471

*/

 



answered Mar 30, 2016 by avibootz
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