Question

How to convert an int into an array of ints in PHP

Answer 1

$n = 78910;

$arr = array_fill(0, 5, 0);
 
for ($i = count($arr) - 1; $i >= 0; $i--)
{
    $arr[$i] = $n % 10;
    $n = $n / 10;
}
 
for ($i = 0; $i < count($arr); $i++)
    echo "arr[" . $i . "] = " . $arr[$i] . "<br />";
     
/*
run:
   
arr[0] = 7
arr[1] = 8
arr[2] = 9
arr[3] = 1
arr[4] = 0
      
*/

 

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Answer 2

$n = 78910;

$arr = array_fill(0, strlen($n), 0);
 
for ($i = count($arr) - 1; $i >= 0; $i--)
{
    $arr[$i] = $n % 10;
    $n = $n / 10;
}
 
for ($i = 0; $i < count($arr); $i++)
    echo "arr[" . $i . "] = " . $arr[$i] . "<br />";
     
/*
run:
   
arr[0] = 7
arr[1] = 8
arr[2] = 9
arr[3] = 1
arr[4] = 0
      
*/

 

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