Question

How to use logical OR (||) operator in TypeScript

Answer 1

const a = 5;
const b = -3;
  
console.log(a > 0 || b > 0);
   
   
     
     
/*
run:
     
true
     
*/

 

 

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Answer 2

console.log(true || true);   // true
console.log(false || true);  // true
console.log(true || false);  // true
console.log(false || false); // false
   

  
    
    
/*
run:
    
true
true
true
false

*/

 

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Answer 3

console.log(true || false && false);
 
console.log((true || false) && false);
   
   
     
     
/*
run:
     
true
false
     
*/

 

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Answer 4

console.log(true  || true); // true
console.log(false || true); // true
console.log(true  || false); // true
console.log(false || (2 == 8)); // false
console.log('c++' || 'typescript'); // c++
console.log(false || 'typescript'); // typescript
console.log('typescript' || false); // typescript
console.log('' || false); // false
console.log(false || ''); // 
 
   
     
     
/*
run:
     
true
true
true
false
c++
typescript
typescript
false
""
     
*/

 

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