How to check if a list contains only distinct (non-repeating) elements in Python

1 Answer

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def containsOnlyUniqueElement(arr):
    size = len(arr)
    st = set(arr)
     
    return len(st) == len(arr)


    
lst = [1, 5, 7, 3, 9, 8, 0, 2]

if (containsOnlyUniqueElement(lst)):
    print("Yes")
else:
    print("No")
   
    
    
'''
run:

Yes

'''

 



answered Dec 7, 2021 by avibootz
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