Question

How to find the length (rows, cols) of 2D array in VB.NET

Answer 1

Imports System
				
Public Module Module1
	Public Sub Main()
		Dim array2d(2, 3) As Integer
 
        Console.WriteLine("rows: {0}", array2d.GetUpperBound(0))
        Console.WriteLine("columns: {0}", array2d.GetUpperBound(1))
	End Sub
End Module




' run:
' 
' rows: 2
' columns: 3
'
 

 

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Answer 2

Imports System
				
Public Module Module1
	Public Sub Main()
		Dim array2d(,) As Integer = New Integer(,) {{1, 8, 5}, 
													{6, 7, 1}}
 		
		Dim rows As Integer = array2d.GetUpperBound(0) + 1
		Dim cols As Integer = array2d.GetUpperBound(1) + 1
		
        Console.WriteLine("rows: {0}", rows)
        Console.WriteLine("columns: {0}", cols)
	End Sub
End Module




' run:
' 
' rows: 2
' columns: 3
'
 

 

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Answer 3

Imports System
				
Public Module Module1
	Public Sub Main()
		Dim array2d(,) As Integer = New Integer(,) {{1, 8, 5}, 
													{6, 7, 1}}
 		
		Dim rows As Integer = array2d.GetLength(0)
		Dim cols As Integer = array2d.GetLength(1)
		
        Console.WriteLine("rows: {0}", rows)
        Console.WriteLine("columns: {0}", cols)
	End Sub
End Module




' run:
' 
' rows: 2
' columns: 3
'
 

 

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Answer 4

Imports System
				
Public Module Module1
	Public Sub Main()
		Dim array2d(2, 3) As Integer
         
        Dim rows As Integer = array2d.GetLength(0) - 1
        Dim cols As Integer = array2d.GetLength(1) - 1
         
        Console.WriteLine("rows: {0}", rows)
        Console.WriteLine("columns: {0}", cols)
	End Sub
End Module




' run:
' 
' rows: 2
' columns: 3
'
 

 

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