Question

How to count all possible 5 permutations of the abc without repetition in Python

Answer 1

from itertools import permutations

abc = "abcdefghijklmnopqrstuvwxyz"
X = 5

p = list(permutations(abc, X))

f = open("words.txt", "w")

count = 0
for item in list(p):
    f.write(item[0] + item[1] + item[2] + item[3] + item[4] + "\n")
    count += 1

print(count)



'''
run:

7893600

'''

 

70+ SQL courses for beginners and professionals